Saturday, March 14, 2009

Prove (paiseh wrong ques)

OMK 2005

4)
Let a and b be non-negative real number. Prove

(ab)^(1/3) + (ab^2)^(1/3)< or = a+b

ab^2 .. square is just for b.
(ab)^(1/3) means ab inside the root（根号）
Posted by at

7 comments:

  1. ⓛⓔⓔⓨⓞⓤⓝⓖⓚⓨⓤMarch 15, 2009 at 10:58 AM

    a=0
    b=0

    Is it correct?

    ReplyDelete
  2. OyicoMarch 15, 2009 at 1:13 PM

    haha you are suppose to prove the statement above, not find the values of a & b. When a and b have any values (of real numbers), the statement is supposed to hold true.

    ReplyDelete
  3. ⓛⓔⓔⓨⓞⓤⓝⓖⓚⓨⓤMarch 15, 2009 at 4:00 PM

    oh...
    ley me think....

    ReplyDelete
  4. Ho KitMarch 16, 2009 at 12:27 PM

    This comment has been removed by the author.

    ReplyDelete
  5. Ho KitMarch 16, 2009 at 12:28 PM

    hei, i got stg 2 ask...
    the a n b muz b non-negative real no., rite?
    den hor they can b 0.1,0.2 n so on, rite?
    den if u let a b 0.1, b b 0.2,
    the statement seemed like 不成立。。。
    or it is my calcuation mistake...
    any1 can correct me???

    ReplyDelete
  6. OyicoMarch 16, 2009 at 5:55 PM

    ya hokit, i got the same result as u too.. a = 0.1, b = 0.2

    ReplyDelete
  7. Ho KitMarch 18, 2009 at 12:25 AM

    @kazekage,
    i think the same thing happen again la...
    u put a=b=0.001...
    den u noe...

    ReplyDelete

Subscribe to: Post Comments (Atom)